9h^2+12=95

Solution for 9h^2+12=95 equation:

9h^2+12=95

We move all terms to the left:

9h^2+12-(95)=0

We add all the numbers together, and all the variables

9h^2-83=0

a = 9; b = 0; c = -83;
Δ = b2-4ac
Δ = 02-4·9·(-83)
Δ = 2988
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2988}=\sqrt{36*83}=\sqrt{36}*\sqrt{83}=6\sqrt{83}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{83}}{2*9}=\frac{0-6\sqrt{83}}{18}
=-\frac{6\sqrt{83}}{18}
=-\frac{\sqrt{83}}{3}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{83}}{2*9}=\frac{0+6\sqrt{83}}{18}
=\frac{6\sqrt{83}}{18}
=\frac{\sqrt{83}}{3}
$